Remove path name from test case
[binutils-gdb.git] / gdb / split-name.c
1 /* Split a symbol name.
2
3 Copyright (C) 2022-2023 Free Software Foundation, Inc.
4
5 This file is part of GDB.
6
7 This program is free software; you can redistribute it and/or modify
8 it under the terms of the GNU General Public License as published by
9 the Free Software Foundation; either version 3 of the License, or
10 (at your option) any later version.
11
12 This program is distributed in the hope that it will be useful,
13 but WITHOUT ANY WARRANTY; without even the implied warranty of
14 MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
15 GNU General Public License for more details.
16
17 You should have received a copy of the GNU General Public License
18 along with this program. If not, see <http://www.gnu.org/licenses/>. */
19
20 #include "defs.h"
21 #include "split-name.h"
22 #include "cp-support.h"
23
24 /* See split-name.h. */
25
26 std::vector<gdb::string_view>
27 split_name (const char *name, split_style style)
28 {
29 std::vector<gdb::string_view> result;
30 unsigned int previous_len = 0;
31
32 switch (style)
33 {
34 case split_style::CXX:
35 for (unsigned int current_len = cp_find_first_component (name);
36 name[current_len] != '\0';
37 current_len += cp_find_first_component (name + current_len))
38 {
39 gdb_assert (name[current_len] == ':');
40 result.emplace_back (&name[previous_len],
41 current_len - previous_len);
42 /* Skip the '::'. */
43 current_len += 2;
44 previous_len = current_len;
45 }
46 break;
47
48 case split_style::UNDERSCORE:
49 /* Handle the Ada encoded (aka mangled) form here. */
50 for (const char *iter = strstr (name, "__");
51 iter != nullptr;
52 iter = strstr (iter, "__"))
53 {
54 result.emplace_back (&name[previous_len],
55 iter - &name[previous_len]);
56 iter += 2;
57 previous_len = iter - name;
58 }
59 break;
60
61 case split_style::DOT_STYLE:
62 /* D and Go-style names. */
63 for (const char *iter = strchr (name, '.');
64 iter != nullptr;
65 iter = strchr (iter, '.'))
66 {
67 result.emplace_back (&name[previous_len],
68 iter - &name[previous_len]);
69 ++iter;
70 previous_len = iter - name;
71 }
72 break;
73
74 default:
75 break;
76 }
77
78 result.emplace_back (&name[previous_len]);
79 return result;
80 }
81